# A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is

A. 5 \frac{15}{17} \% \text { loss }
B. 5 \frac{15}{17} \% \text { gain }
C. 6 \frac{2}{3} \% \text { gain }
D. 6 \frac{2}{3} \% \text { loss }

The correct answer is5 \frac{15}{17} \% \text { gain }
Question: The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

Step by Step Solution:

To solve this problem, we will use these 3 formula’s.
1. C P1=\left(\frac{100}{(100+\text { profit } \%)} \times S P\right)

2. C P2=\left(\frac{100}{(100-\text { loss } \%)} \times S P\right)

3. \text { Gain } \%\ =\ \left(\frac{Selling\ price\ -\ Cost\ price}{Cost\ price}\ \times\ 100\right)\%

Step: 1

C P1=\left(\frac{100}{(100+\text { 20 })} \times 840\right)

C.P1 = RS. 700

Step: 2
Now the cost price of another transition;

C P2=\left(\frac{100}{(100-\text { 4 })} \times 960\right)

C.P2= RS. 1000

Step: 3
Total Cost price = C.P1 + CP2
Total Cost price = RS. 700 + RS. 1000
Total Cost price = RS. 1700

∴ Total Selling price = RS. 840 + RS. 960 = RS. 1800

Step: 4
so the selling price is more than the cost price, the shopkeeper is in gain;

\text { Gain } \%\ =\ \left(\frac{Selling\ price\ -\ Cost\ price}{Cost\ price}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{1800\ -\ 1700}{1700}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{100}{1700}\ \times\ 100\right)\%

\text { Gain } \%\ = 5 \frac{15}{17} \%

Hence, Shopkeeper total gain is 5 \frac{15}{17} \%
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