Arithmetic Aptitude MCQ (Multiple Choice Questions)

In a class of CSS, there are 70% girls if there are 25 boys, how many total students are in the class?

A. 83.3
B. 90
C. 80
D. 70

Answer & Solution

Answer: The correct answer is 83.3 students.

Solution:

Let x be total students in a class.

If there are 70% girls in class, it means 30% are boys.
we can write it as:
⇒ 30% of students in class = 25 boys

The equation will be:
⇒ \frac{30}{100}\times x\ =\ 25

Keep the x on left side, and bring other value to right side
it will become,

x\ =\ \frac{25\times100}{30}

x\ =\ \frac{5\times100}{6}

x\ =\ \frac{500}{6}

x=\ 83.3

Hence, There are total 83.3 students in the class.
What percent is 3/12?

A. 25%
B. 30%
C. 35%
D. 40%

Answer & Solution

Answer: The correct answer is 25%.

Solution:

By using Substitution we form an equation

What\ \ \ \ \ Percent\ \ \ \ \ is\ \ \ \ \ \ \frac{3}{12}
\downarrow\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \ \downarrow\
x\ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{1}{100}\ \ \ \ \ \ \ \ \ \ =\ \ \ \ \ \ \frac{3}{12}

x\ \times\frac{1}{100}=\frac{3}{12}

x\ =\frac{3}{12}\times100

x\ =\frac{1}{4}\times100\ \ OR\ \ \frac{300}{12}

x\ =\ 25\%

Hence, 25 percentage is 3/12.

Alternate Method:

Also if the question is given like this: Convert 3/12 into percentage
you can solve it in simple way. Just multiply it with 100 to convert any number in percentage.

x\ =\frac{3}{12}\times100

x\ =\frac{1}{4}\times100\ \ OR\ \ \frac{300}{12}

x\ =\ 25\%
What is 10 percent of 350?

A. 40
B. 38
C. 35
D. 45

Answer & Solution

Answer: The correct answer is 35.

Solution:
By using Substitution we form an equation

What\ \ \ is\ \ \ 10\%\ \ \ of\ \ \ 350

\downarrow\ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \downarrow\

x\ \ \ \ \ \ \ =\ \ \ \frac{10}{100}\ \ \ \ \times\ \ \ 350

x\ =\frac{10}{100}\times350

x\ =\ \frac{10\ \times350}{100}

x\ =\ \frac{3500}{100}

x\ =\ 35

Hence, 35 is 10 percent of 350.
8 is what percent of 6?

A. 133
B. 140
C. 130
D. none of these

Answer & Solution

Answer: The correct answer is 133.

Solution:

Lets form an equation
8\ \ \ is\ \ \ what\ \ \ percent\ \ \ of\ \ \ 6

\downarrow\ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \downarrow\

8\ \ \ =\ \ \ \ \ \ x\ \ \ \ \ \ \ \ \frac{1}{100}\ \ \ \ \ \times\ \ \ \ \ 6

⇒\ \ 8\ =\ x.\ \frac{1}{100}\times6

⇒\ \ 8\ \times100\ =\ x\times6

⇒\ \ \frac{800}{6}\ =\ x

x\ =\ 133

Hence, 8 is 133 percent of 6.
What percent of 24 is 18?

A. 25%
B. 30%
C. 35%
D. 75%

Answer & Solution

Answer: The correct answer is 75%.

Solution:

By using Substitution we form an equation
What\ \ \ \ \ Percent\ \ \ \ \ \ of\ \ \ \ \ \ 24\ \ \ \ \ \ \ is\ \ \ \ \ \ 18

\downarrow\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\

x\ \ \ \ \ \ \ \ \ \ \ \ \ \frac{1}{100}\ \ \ \ \ \ \ \ \ \ \ \times\ \ \ \ \ \ 24\ \ \ \ \ \ =\ \ \ \ \ \ 18

⇒\ \frac{x}{100}\times24\ =\ 18

⇒\ \ x\ \times24\ =\ 18\ \times100

⇒\ \ x\ =\frac{18\ \times100}{24}

x\ =\ 75\%


Hence, 75% of 24 is 18.
In an examination, 80% of candidates passed in English and 85% candidates passed in Mathematics. If 73% of candidates passed in both these subjects, then what percent of candidates failed in both the subjects?

A. 8%
B. 15%
C. 27%
D. 35%

Answer & Solution

Answer: The correct answer is 8%.

Solution:

The number of candidates who failed in both subjects = Total number of candidates – The number of candidates who passed in both subjects

Candidates passed in English = 80%

Candidates passed in Mathematics = 85%
Candidates passed in both subjects = 73%
Total number of candidates passed = (80+85 -73)

= 92%. 

Now,

Candidates failed in both subjects = 100% – 92% = 8%.

Hence, the percentage of candidates who failed in both subjects is 8%.
Half percent, written as a decimal, is

A. 0.2
B. 0.02
C. 0.005
D. 0.05

Answer & Solution

Answer: The correct answer is 0.005.

Solution:

we know that,

1\%\ =\ \frac{1}{100}

so,

\frac{1}{2}\%\ =\ \frac{1}{2}\ \times\ \frac{1}{100}

\frac{1}{2}\%\ =\ \frac{1}{200}

\frac{1}{2}\%\ = 0.005

Hence, Half percent, written as a decimal, is 0.005.
1.14 expressed as a per cent of 1.9 is

A. 6%
B. 10%
C. 60%
D. 90%

Answer & Solution

Answer: The correct answer is 60%.

Solution:

we know the percentage formula;
p\ =\ \frac{x}{n}\ \times100
where,
x = given value
n = total value or amount
p= percentage of given value compared to total

According to the statement,
x = 1.14 and n= 1.9
so,

p\ =\ \frac{1.14}{1.9}\ \times100

p = 60%

Hence, the percentage is 60%.
A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is

A. 5%
B. 8%
C. 10%
D. No profit, no loss

Check Answer

The correct answer is “5%”
Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is;

Step by Step Solution:

We will use this formula to find price;
price = units × rate

Step: 1

The cost price of 26Kg rice = (26 × 20)
The cost price of 26Kg rice = RS. 520

The Cost price of 30Kg rice = (30 × 36)
The cost price of 30Kg rice = RS. 1080

The total cost price of 56Kg rice = RS. 520 + RS. 1080
The total cost price of 56Kg rice = RS. 1600

Step: 2

The selling price of 56Kg rice = (56 × 30)
The selling price of 56Kg rice = RS. 1680

Step: 3

\text { Gain } \%\ =\ \left(\frac{Selling\ price\ -\ Cost\ price}{Cost\ price}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{1680\ -\ 1600}{1600}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{80}{1600}\ \times\ 100\right)\%

Gain % = 5%

Hence, the trader profit % is 5%
A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is

A. 5 \frac{15}{17} \% \text { loss }
B. 5 \frac{15}{17} \% \text { gain }
C. 6 \frac{2}{3} \% \text { gain }
D. 6 \frac{2}{3} \% \text { loss }

Check Answer

The correct answer is “5 \frac{15}{17} \% \text { gain }“
Question: The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

Step by Step Solution:

To solve this problem, we will use these 3 formula’s.
1. C P1=\left(\frac{100}{(100+\text { profit } \%)} \times S P\right)

2. C P2=\left(\frac{100}{(100-\text { loss } \%)} \times S P\right)

3. \text { Gain } \%\ =\ \left(\frac{Selling\ price\ -\ Cost\ price}{Cost\ price}\ \times\ 100\right)\%

Step: 1

C P1=\left(\frac{100}{(100+\text { 20 })} \times 840\right)

C.P1 = RS. 700

Step: 2
Now the cost price of another transition;

C P2=\left(\frac{100}{(100-\text { 4 })} \times 960\right)

C.P2= RS. 1000

Step: 3
Total Cost price = C.P1 + CP2
Total Cost price = RS. 700 + RS. 1000
Total Cost price = RS. 1700

∴ Total Selling price = RS. 840 + RS. 960 = RS. 1800

Step: 4
so the selling price is more than the cost price, the shopkeeper is in gain;

\text { Gain } \%\ =\ \left(\frac{Selling\ price\ -\ Cost\ price}{Cost\ price}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{1800\ -\ 1700}{1700}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{100}{1700}\ \times\ 100\right)\%

\text { Gain } \%\ = 5 \frac{15}{17} \%

Hence, Shopkeeper total gain is 5 \frac{15}{17} \%
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