# Arithmetic Aptitude MCQ (Multiple Choice Questions)

A. 83.3
B. 90
C. 80
D. 70

Solution:

Let x be total students in a class.

If there are 70% girls in class, it means 30% are boys.
we can write it as:
⇒ 30% of students in class = 25 boys

The equation will be:
\frac{30}{100}\times x\ =\ 25

Keep the x on left side, and bring other value to right side
it will become,

x\ =\ \frac{25\times100}{30}

x\ =\ \frac{5\times100}{6}

x\ =\ \frac{500}{6}

x=\ 83.3

Hence, There are total 83.3 students in the class.

A. 25%
B. 30%
C. 35%
D. 40%

Solution:

By using Substitution we form an equation

What\ \ \ \ \ Percent\ \ \ \ \ is\ \ \ \ \ \ \frac{3}{12}
\downarrow\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \ \downarrow\
x\ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{1}{100}\ \ \ \ \ \ \ \ \ \ =\ \ \ \ \ \ \frac{3}{12}

x\ \times\frac{1}{100}=\frac{3}{12}

x\ =\frac{3}{12}\times100

x\ =\frac{1}{4}\times100\ \ OR\ \ \frac{300}{12}

x\ =\ 25\%

Hence, 25 percentage is 3/12.

Alternate Method:

Also if the question is given like this: Convert 3/12 into percentage
you can solve it in simple way. Just multiply it with 100 to convert any number in percentage.

x\ =\frac{3}{12}\times100

x\ =\frac{1}{4}\times100\ \ OR\ \ \frac{300}{12}

x\ =\ 25\%

A. 40
B. 38
C. 35
D. 45

Solution:
By using Substitution we form an equation

What\ \ \ is\ \ \ 10\%\ \ \ of\ \ \ 350

\downarrow\ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \downarrow\

x\ \ \ \ \ \ \ =\ \ \ \frac{10}{100}\ \ \ \ \times\ \ \ 350

x\ =\frac{10}{100}\times350

x\ =\ \frac{10\ \times350}{100}

x\ =\ \frac{3500}{100}

x\ =\ 35

Hence, 35 is 10 percent of 350.

A. 133
B. 140
C. 130
D. none of these

Solution:

Lets form an equation
8\ \ \ is\ \ \ what\ \ \ percent\ \ \ of\ \ \ 6

\downarrow\ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \downarrow\

8\ \ \ =\ \ \ \ \ \ x\ \ \ \ \ \ \ \ \frac{1}{100}\ \ \ \ \ \times\ \ \ \ \ 6

⇒\ \ 8\ =\ x.\ \frac{1}{100}\times6

⇒\ \ 8\ \times100\ =\ x\times6

⇒\ \ \frac{800}{6}\ =\ x

x\ =\ 133

Hence, 8 is 133 percent of 6.

A. 25%
B. 30%
C. 35%
D. 75%

Solution:

By using Substitution we form an equation
What\ \ \ \ \ Percent\ \ \ \ \ \ of\ \ \ \ \ \ 24\ \ \ \ \ \ \ is\ \ \ \ \ \ 18

\downarrow\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\ \ \ \ \ \ \ \ \downarrow\

x\ \ \ \ \ \ \ \ \ \ \ \ \ \frac{1}{100}\ \ \ \ \ \ \ \ \ \ \ \times\ \ \ \ \ \ 24\ \ \ \ \ \ =\ \ \ \ \ \ 18

⇒\ \frac{x}{100}\times24\ =\ 18

⇒\ \ x\ \times24\ =\ 18\ \times100

⇒\ \ x\ =\frac{18\ \times100}{24}

x\ =\ 75\%

Hence, 75% of 24 is 18.

A. 8%
B. 15%
C. 27%
D. 35%

Solution:

The number of candidates who failed in both subjects = Total number of candidates – The number of candidates who passed in both subjects

Candidates passed in English = 80%

Candidates passed in Mathematics = 85%
Candidates passed in both subjects = 73%
Total number of candidates passed = (80+85 -73)

= 92%.

Now,

Candidates failed in both subjects = 100% – 92% = 8%.

Hence, the percentage of candidates who failed in both subjects is 8%.

A. 0.2
B. 0.02
C. 0.005
D. 0.05

Solution:

we know that,

1\%\ =\ \frac{1}{100}

so,

\frac{1}{2}\%\ =\ \frac{1}{2}\ \times\ \frac{1}{100}

\frac{1}{2}\%\ =\ \frac{1}{200}

\frac{1}{2}\%\ = 0.005

Hence, Half percent, written as a decimal, is 0.005.

A. 6%
B. 10%
C. 60%
D. 90%

Solution:

we know the percentage formula;
p\ =\ \frac{x}{n}\ \times100
where,
x = given value
n = total value or amount
p= percentage of given value compared to total

According to the statement,
x = 1.14 and n= 1.9
so,

p\ =\ \frac{1.14}{1.9}\ \times100

p = 60%

Hence, the percentage is 60%.

A. 5%
B. 8%
C. 10%
D. No profit, no loss

Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is;

Step by Step Solution:

We will use this formula to find price;
price = units × rate

Step: 1

The cost price of 26Kg rice = (26 × 20)
The cost price of 26Kg rice = RS. 520

The Cost price of 30Kg rice = (30 × 36)
The cost price of 30Kg rice = RS. 1080

The total cost price of 56Kg rice = RS. 520 + RS. 1080
The total cost price of 56Kg rice = RS. 1600

Step: 2

The selling price of 56Kg rice = (56 × 30)
The selling price of 56Kg rice = RS. 1680

Step: 3

\text { Gain } \%\ =\ \left(\frac{Selling\ price\ -\ Cost\ price}{Cost\ price}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{1680\ -\ 1600}{1600}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{80}{1600}\ \times\ 100\right)\%

Gain % = 5%

Hence, the trader profit % is 5%

A. 5 \frac{15}{17} \% \text { loss }
B. 5 \frac{15}{17} \% \text { gain }
C. 6 \frac{2}{3} \% \text { gain }
D. 6 \frac{2}{3} \% \text { loss }

The correct answer is5 \frac{15}{17} \% \text { gain }
Question: The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:

Step by Step Solution:

To solve this problem, we will use these 3 formula’s.
1. C P1=\left(\frac{100}{(100+\text { profit } \%)} \times S P\right)

2. C P2=\left(\frac{100}{(100-\text { loss } \%)} \times S P\right)

3. \text { Gain } \%\ =\ \left(\frac{Selling\ price\ -\ Cost\ price}{Cost\ price}\ \times\ 100\right)\%

Step: 1

C P1=\left(\frac{100}{(100+\text { 20 })} \times 840\right)

C.P1 = RS. 700

Step: 2
Now the cost price of another transition;

C P2=\left(\frac{100}{(100-\text { 4 })} \times 960\right)

C.P2= RS. 1000

Step: 3
Total Cost price = C.P1 + CP2
Total Cost price = RS. 700 + RS. 1000
Total Cost price = RS. 1700

∴ Total Selling price = RS. 840 + RS. 960 = RS. 1800

Step: 4
so the selling price is more than the cost price, the shopkeeper is in gain;

\text { Gain } \%\ =\ \left(\frac{Selling\ price\ -\ Cost\ price}{Cost\ price}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{1800\ -\ 1700}{1700}\ \times\ 100\right)\%

\text { Gain } \%\ =\ \left(\frac{100}{1700}\ \times\ 100\right)\%

\text { Gain } \%\ = 5 \frac{15}{17} \%

Hence, Shopkeeper total gain is 5 \frac{15}{17} \%